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Measurement Device Independent Quantum Digital Signature (MDI-QDS) (edit)
Revision as of 08:01, 3 June 2019
, 3 June 2019→Subroutine: MDI-KGP(Seller, Receiver R, Arbitrator,i)
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####If (<math>|\Psi\rangle=\frac{1}{\sqrt{2}}(|01\rangle+|10\rangle))||(|Psi\rangle=\frac{1}{\sqrt{2}}(|01\rangle-|10\rangle)</math>) '''then''' <math>R^i(k)=\tilde b</math> | ####If (<math>|\Psi\rangle=\frac{1}{\sqrt{2}}(|01\rangle+|10\rangle))||(|Psi\rangle=\frac{1}{\sqrt{2}}(|01\rangle-|10\rangle)</math>) '''then''' <math>R^i(k)=\tilde b</math> | ||
###If (<math>s_{\text{basis}}=r_{\text{basis}}=X</math>) | ###If (<math>s_{\text{basis}}=r_{\text{basis}}=X</math>) | ||
####If (<math>|\Psi\rangle=\frac{1}{\sqrt{2}}(|++\rangle+|--\rangle))||(|Psi\rangle=\frac{1}{\sqrt{2}}(|+-\rangle+|-+\rangle)</math>) '''then''' <math>R^i(k)=b</ | ####If (<math>|\Psi\rangle=\frac{1}{\sqrt{2}}(|++\rangle+|--\rangle))||(|Psi\rangle=\frac{1}{\sqrt{2}}(|+-\rangle+|-+\rangle)</math>) '''then''' <math>R^i(k)=b</math> | ||
####If (<math>|\Psi\rangle=\frac{1}{\sqrt{2}}(|++\rangle-|--\rangle))||(|Psi\rangle=\frac{1}{\sqrt{2}}(|01\rangle-|+-\rangle)</math>) '''then''' <math>R^i(k)=\tilde b</math> | ####If (<math>|\Psi\rangle=\frac{1}{\sqrt{2}}(|++\rangle-|--\rangle))||(|Psi\rangle=\frac{1}{\sqrt{2}}(|01\rangle-|+-\rangle)</math>) '''then''' <math>R^i(k)=\tilde b</math> | ||
* | * | ||