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Dual Basis Measurement Based Protocol: Difference between revisions
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# <p>One of the voters prepares <math> N+N2^{\delta_0}</math> states of the form <math>|D_1\rangle=\dfrac{1}{\sqrt{m^{N-1}}}\sum_{\sum_{k=1}^{N}i_k=0\text{ } mod \text{ }c}|i_1\rangle|i_2\rangle...|i_N\rangle </math> and <math> 1 + N2^{\delta_0}</math> states of the form <math> |D_2\rangle=\dfrac{1}{\sqrt{N!}}\sum_{(i_1,i_2,...,i_N)\in P_N}|i_1\rangle|i_2\rangle...|i_N\rangle </math>. </p> Each voter <math>V_k</math> receives kth particle from each of the states. | # <p>One of the voters prepares <math> N+N2^{\delta_0}</math> states of the form <math>|D_1\rangle=\dfrac{1}{\sqrt{m^{N-1}}}\sum_{\sum_{k=1}^{N}i_k=0\text{ } mod \text{ }c}|i_1\rangle|i_2\rangle...|i_N\rangle </math> and <math> 1 + N2^{\delta_0}</math> states of the form <math> |D_2\rangle=\dfrac{1}{\sqrt{N!}}\sum_{(i_1,i_2,...,i_N)\in P_N}|i_1\rangle|i_2\rangle...|i_N\rangle </math>. </p> Each voter <math>V_k</math> receives kth particle from each of the states. | ||
# Voter <math>V_k</math> chooses at random <math>2^{\delta_0}</math> of the <math>|D_1\rangle</math> states. The other voters measure half of their particles in the computational and half in the Fourier basis.if the chosen basis is computational: | # Voter <math>V_k</math> chooses at random <math>2^{\delta_0}</math> of the <math>|D_1\rangle</math> states. The other voters measure half of their particles in the computational and half in the Fourier basis.if the chosen basis is computational: | ||
** the measurement results need to add up to 0,** else: the measurement results are all the same. All voters simultaneously broadcast their results and if one of them notices a discrepancy, the protocol aborts.<p> The states <math>|D_2\rangle</math> are similarly checked.</p> | ** the measurement results need to add up to 0, | ||
** else: the measurement results are all the same. All voters simultaneously broadcast their results and if one of them notices a discrepancy, the protocol aborts.<p> The states <math>|D_2\rangle</math> are similarly checked.</p> | |||
#<p> All voters measure their qudits in the computational basis.</p> Then each <math>V_k</math> holds a blank ballot of dimension N with the measurement outcomes corresponding to parts of <math>|D_1\rangle </math> states <math>B_k = [\xi_k^{1}...\xi_k^{sk_k}...\xi_k^{N}]^{T}</math> and a unique index, <math>sk_k \in \{1,...,N\}</math> from the measurement outcome of the qudit that belongs to <math>|D_2\rangle</math>. | #<p> All voters measure their qudits in the computational basis.</p> Then each <math>V_k</math> holds a blank ballot of dimension N with the measurement outcomes corresponding to parts of <math>|D_1\rangle </math> states <math>B_k = [\xi_k^{1}...\xi_k^{sk_k}...\xi_k^{N}]^{T}</math> and a unique index, <math>sk_k \in \{1,...,N\}</math> from the measurement outcome of the qudit that belongs to <math>|D_2\rangle</math>. | ||