Classical Fully Homomorphic Encryption for Quantum Circuits: Difference between revisions

Jump to navigation Jump to search
m
Line 76: Line 76:
####Server generates following superposition sampled over random distribution D\sqrt{D(\mu,r)}|\mu,r\rangle</math>
####Server generates following superposition sampled over random distribution D\sqrt{D(\mu,r)}|\mu,r\rangle</math>
#### Servers then entangles the two superposition states on quantum input and random distribution D with a third register for function output as follows:</br><math>\sum_{a,b,\mu\in\{0,1\},r}\alpha_{ab}\sqrt{D(\mu,r)}|a,b\rangle|\mu,r\rangle|f_a(r)\rangle</math>,</br> such that  <math>f_0=AltHE.Enc_{pk}();f_1(\mu_1,r_1)=f_0 (\mu_0,r_0)\oplus_H \hat{c}=AltHE.Enc_{pk}(\mu_0,r_0)\oplus_H AltHE.Enc_{pk}(s)</math>  
#### Servers then entangles the two superposition states on quantum input and random distribution D with a third register for function output as follows:</br><math>\sum_{a,b,\mu\in\{0,1\},r}\alpha_{ab}\sqrt{D(\mu,r)}|a,b\rangle|\mu,r\rangle|f_a(r)\rangle</math>,</br> such that  <math>f_0=AltHE.Enc_{pk}();f_1(\mu_1,r_1)=f_0 (\mu_0,r_0)\oplus_H \hat{c}=AltHE.Enc_{pk}(\mu_0,r_0)\oplus_H AltHE.Enc_{pk}(s)</math>  
####Server measures the last register to get a secret text (function output) <math>y = AltHE.Enc_{pk}(\mu_0,r_0)=AltHE.Enc_{pk}(\mu_1,r_1)\oplus_H AltHE.Enc_{pk}(s)</math>, thus, <math>\mu_0=\mu_1\oplus_H s</math>.
####Server measures the last register to get a secret text (function output) <math>y = AltHE.Enc_{pk}(\mu_0,r_0)=AltHE.Enc_{pk}(\mu_1,r_1)\oplus_H AltHE.Enc_{pk}(s)</math>.
####Server performs Hadamard on second register and measures it to get a string d such that first register of input quantum state is reduced to the following ideal state:</br><math>(Z^{d\cdot ((\mu_0,r_0)\oplus (\mu_1,r_1))}\otimes X^{\mu_0})\textrm{CNOT}_{1,2}^s|\psi\rangle</math> </br>where <math>AltHE.Enc_{pk}(\mu_0;r_0) = AltHE.Enc_{pk}(\mu_1;r_1) \oplus_H \hat{c}</math> and <math>\oplus_H</math> is the homomorphic XOR operation.
####Server performs Hadamard on second register and measures it to get a string d such that first register of input quantum state is reduced to the following ideal state:</br><math>(Z^{d\cdot ((\mu_0,r_0)\oplus (\mu_1,r_1))}\otimes X^{\mu_0})\textrm{CNOT}_{1,2}^s|\psi\rangle</math> </br>where <math>(\mu_0,r_0)=(\mu_1,r_1)\oplus_H s</math> as <math>\oplus_H</math> is the homomorphic XOR operation.
####The server uses <math>pk_{i+1}</math> to compute HE.Enc<math>_{pk_{i+1}}(c_{x,z,pk_i})</math> and HE.Enc<math>_{pk_{i+1}}(\hat{c},y,d)</math>.  
####The server uses <math>pk_{i+1}</math> to compute HE.Enc<math>_{pk_{i+1}}(c_{x,z,pk_i})</math> and HE.Enc<math>_{pk_{i+1}}(\hat{c},y,d)</math>.  
####The server computes the encryption of <math>x,z</math> under <math>pk_{i+1}</math> by homomorphically running the decryption circuit on inputs <math>\mathrm{HE.Enc}_{pk_{i+1}}(sk_i)</math> and HE.Enc<math>_{pk_{i+1}}(c_{x,z,pk_i})</math>.
####The server computes the encryption of <math>x,z</math> under <math>pk_{i+1}</math> by homomorphically running the decryption circuit on inputs <math>\mathrm{HE.Enc}_{pk_{i+1}}(sk_i)</math> and HE.Enc<math>_{pk_{i+1}}(c_{x,z,pk_i})</math>.
Write, autoreview, editor, reviewer
3,129

edits

Navigation menu