Editing Quantum voting based on conjugate coding

Jump to navigation Jump to search
Warning: You are not logged in. Your IP address will be publicly visible if you make any edits. If you log in or create an account, your edits will be attributed to your username, along with other benefits.

The edit can be undone. Please check the comparison below to verify that this is what you want to do, and then publish the changes below to finish undoing the edit.

Latest revision Your text
Line 34: Line 34:


==Protocol Description==
==Protocol Description==
*'''Setup phase''':
#EA picks a vector <math> \bar{b} = (b_1, . . . , b_{n+1}) \in \{0, 1\}^{n+1}</math> that will be kept secret from T until the end of the ballot casting phase.
#For each <math>V_k</math>, EA prepares w = poly(n) blank ballot fragments each of the form <math>|\phi_{\bar{a}_j,\bar{b}}\rangle=|\psi_{a_j^1,b_1}\rangle \otimes ...\otimes |\psi_{a_j^{n+1},b_{n+1}}\rangle,j \in \{1,...,w\}</math> where <math>\bar{a}_j=(a_j^1,...,a_j^{n+1}) </math> such that <math>(a_j^1,...,a_j^{n})\in \{0,1\}^n,a_j^{n+1}=a_j^1 \oplus ...\oplus a_j^{n}</math> and <math> |\psi_{0,0}\rangle=|0\rangle,|\psi_{1,0}\rangle=|1\rangle,|\psi_{0,1}\rangle=\dfrac{1}{\sqrt{2}}(|0\rangle+|1\rangle),|\psi_{1,1}\rangle=\dfrac{1}{\sqrt{2}}(|0\rangle-|1\rangle)  </math>
#EA sends one blank ballot to each <math> V_k </math> over an authenticated channel.
*'''Casting phase''':
#Each <math> V_k</math> picks for each blank ballot fragment a vector <math>\bar{d_j} = (d^1_j , . . . , d^{n+1}_j )</math> such that: <math>(d_j^1,...,d_j^{n})\in \{0,1\}^n,d_j^{n+1}=d_j^1 \oplus ...\oplus d_j^{n}</math><p><math> \forall j \in \{1,...,w\},V_k </math>applies the unitary <math>U^{\bar{d}_j}_j=Y^{d_j^1}\otimes ... \otimes Y^{d_j^{n+1}}</math> to the blank ballot fragment <math>|\phi_{\bar{a}_j,\bar{b}}\rangle</math> where <math display="block"> Y^1=\begin{bmatrix}
    0 & -1  \\
    1 & 0
\end{bmatrix} ,Y^0=I </math> <math>V_k</math> encodes the candidate of choice in the (n + 1)th-qubit of the last blank ballot fragments.</p>
#<p><math> V_k</math> sends the ballot to T over an anonymous channel.
</p>
*'''Tally phase''':
#EA announces <math>\bar{b}</math> to T.
#T decodes each ballot fragment by measuring it in the basis described by vector <math>\bar{b}</math> and XORs the resulting bits and does this to each ballot fragment ending up with a string, which is the actual vote cast.
#T announces the election result.


==Further Information==
==Further Information==


<div style='text-align: right;'>''*contributed by Sara Sarfaraz''</div>
<div style='text-align: right;'>''*contributed by Sara Sarfaraz''</div>
Please note that all contributions to Quantum Protocol Zoo may be edited, altered, or removed by other contributors. If you do not want your writing to be edited mercilessly, then do not submit it here.
You are also promising us that you wrote this yourself, or copied it from a public domain or similar free resource (see Quantum Protocol Zoo:Copyrights for details). Do not submit copyrighted work without permission!

To protect the wiki against automated edit spam, we kindly ask you to solve the following CAPTCHA:

Cancel Editing help (opens in new window)
Retrieved from "https://wiki.veriqloud.fr/index.php?title=Quantum_voting_based_on_conjugate_coding"