Weak String Erasure: Difference between revisions

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# For <math>i</math> in <math>[n]</math> do:
# For <math>i</math> in <math>[n]</math> do:
## Alice chooses uniformly at random <math>\Theta_i \in\{0,1\}</math> and <math>X_i \in \{0,1\}</math>.
## Alice chooses uniformly at random <math>\Theta_i \in\{0,1\}</math> and <math>X_i \in \{0,1\}</math>.
## Alice prepares the state <math>H^{\Theta_i} \ket{X_i}</math>. She sends it over to Bob.
## Alice prepares the state <math>H^{\Theta_i} |X_i\rangle</math>. She sends it over to Bob.
## Bob announces receiving a state.
## Bob announces receiving a state.
## Bob chooses uniformly at random <math>\hat \Theta_i \in\{0,1\}</math>.
## Bob chooses uniformly at random <math>\hat \Theta_i \in\{0,1\}</math>.
## Bob measures the incoming qubit in the standard basis if <math>\hat \Theta_i=0</math> and in the Hadamard basis otherwise. He gets outcome <math>\hat X_i</math></br>
## Bob measures the incoming qubit in the standard basis if <math>\hat \Theta_i=0</math> and in the Hadamard basis otherwise. He gets outcome <math>\hat X_i</math>
At this stage Alice has string <math>X_1^n</math> and <math>\Theta_1^n</math>, and Bob has strings <math>\hat X_1^n</math> and <math>\hat \Theta_1^n</math>.
*At this stage Alice has string <math>X_1^n</math> and <math>\Theta_1^n</math>, and Bob has strings <math>\hat X_1^n</math> and <math>\hat \Theta_1^n</math>.
# Alice and Bob wait for time <math>\Delta t</math>.
# Alice and Bob wait for time <math>\Delta t</math>.
# Alice sends <math>\Theta_1^n</math> to Bob.
# Alice sends <math>\Theta_1^n</math> to Bob.
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